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Proof step 14 from proof min-rec (previous step)

i < min(ints), min(i ' + ints) < i, min(i ' + ints) < min(ints), ∀ i0. i0 ∈ ints → min(i ' + ints) ≤ i0, i ∈ ints → min(ints) ≤ i, ∀ i. i ∈ ints → min(ints) ≤ i ⊦ ints = [], min(i ' + ints) = i

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 15:
i < min(ints), min(i ' + ints) < i, min(i ' + ints) < min(ints), ∀ i. i ∈ ints → min(ints) ≤ i, ∀ i0. i0 ∈ ints → min(i ' + ints) ≤ i0 ⊦ ints = [], min(i ' + ints) = i, i ∈ ints

Rule argument

Additional information

Used simplifier rules: lels-03: ⊦ i < j → (¬ ¬ j ≤ i ↔ false); from specification int-abs