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Proof step 15 from proof primes-rec (previous step)

∀ i. (∀ i0. i0 = i ∨ i0 ∈ ints0 → prime(i0)) → prime(i) ∧ (∀ i. i ∈ ints0 → prime(i)), ∀ i1. i1 = i ∨ i1 = i0 ∨ i1 ∈ ints0 → prime(i1) ⊦ prime(i), prime(i) ∧ (i1 = i0 ∨ i1 ∈ ints0 → prime(i1))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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