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Proof step 16 from proof primes-rec (previous step)

∀ i. (∀ i0. i0 = i ∨ i0 ∈ ints0 → prime(i0)) → prime(i) ∧ (∀ i. i ∈ ints0 → prime(i)), ∀ i1. i1 = i ∨ i1 = i0 ∨ i1 ∈ ints0 → prime(i1) ⊦ prime(i)

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 2 terms: i

Additional information

Used terms: i