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Proof step 4 from proof band-011x-is-unsigned-fix (previous step)

¬(i→n(i) ≤ # int2bits(j) ∧ 0 < i), 0 < i ⊦ band(j, 2 ^ i - 1) = bits2uint(fix(i→n(i), int2bits(j)))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
# int2bits(j) < i→n(i), 0 < i ⊦ band(j, 2 ^ i - 1) = bits2uint(fix(i→n(i), int2bits(j))), i = 0

Rule argument

Additional information

Used simplifier rules: ⊦ i→n(i) = 0 ↔ i = 0;% ⊦ m < n → n ≠ 0; (forward)% ⊦ i < j → (¬ ¬ j ≤ i ↔ false);% ⊦ ¬ i < j ↔ j ≤ i;% ⊦ ¬ m ≤ n ↔ n < m;