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Proof step 5 from proof band-011x-is-unsigned-fix (previous step)

# int2bits(j) < i→n(i), 0 < i ⊦ band(j, 2 ^ i - 1) = bits2uint(fix(i→n(i), int2bits(j))), i = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ ¬ n < # bits → fix(n, bits) = fillsgn(n, bits)
Proof step 7:
¬ i→n(i) < # int2bits(j), # int2bits(j) < i→n(i), 0 < i ⊦ band(j, 2 ^ i - 1) = bits2uint(fillsgn(i→n(i), int2bits(j))), i = 0

Rule argument

seq: ⊦ ¬ n < # bits → fix(n, bits) = fillsgn(n, bits) subst: [bits, n] → [int2bits(j), i→n(i)] rotate: F spec: bitopsaux inst: name: fix-shorter

Additional information

Used simplifier rules: ⊦ m < n → ¬ n < m; Used terms: int2bits(j), i→n(i)