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Proof step 5 from proof band-associativity (previous step)

⊦ bits2int(bitsand(int2bits(i), sgn(bitsand(int2bits(i0), int2bits(j))))) = bits2int(bitsand(sgn(bitsand(int2bits(i), int2bits(i0))), int2bits(j))), bitsand(int2bits(i), sgn(bitsand(int2bits(i0), int2bits(j)))) ≠ [] ∧ bitsand(sgn(bitsand(int2bits(i), int2bits(i0))), int2bits(j)) ≠ []

User applied rule case distinction

And obtained the following new goals

Rule argument

pos: right 2

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