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Proof step 6 from proof band-associativity (previous step)

⊦ bitsand(int2bits(i), sgn(bitsand(int2bits(i0), int2bits(j)))) ≠ [], bits2int(bitsand(int2bits(i), sgn(bitsand(int2bits(i0), int2bits(j))))) = bits2int(bitsand(sgn(bitsand(int2bits(i), int2bits(i0))), int2bits(j)))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
bitsand(int2bits(i), sgn(bitsand(int2bits(i0), int2bits(j)))) = [] ⊦ bits2int([]) = bits2int(bitsand(sgn(bitsand(int2bits(i), int2bits(i0))), int2bits(j)))

Proof step 6 from proof band-associativity (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information