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Proof step 15 from proof bitsand-app-false (previous step)

bits2 = bits3 + boolvar ', # bits2 < # bits0, ∀ bits, bits0, bits1. # bits1 < # bits2 → # bits1 < # bits0 → bitsand(bits + bits0, false ' + bits1) = bitsand(bits0, false ' + bits1) ∨ bits0 = [] ⊦ # bits + # bits0 = 0, bits2 = [], bits0 = [], bitsand(bits + bits0.butlast, false ' + bits3) + (bits0.last ∧ boolvar)' = bitsand(bits0, false ' + bits2), # bits0 = 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 16:
# bits3 + 1 < # bits0, ∀ bits, bits0, bits1. # bits1 < #(bits3 + boolvar ') → # bits1 < # bits0 → bitsand(bits + bits0, false ' + bits1) = bitsand(bits0, false ' + bits1) ∨ bits0 = [] ⊦ # bits + # bits0 = 0, bits0 = [], bitsand(bits + bits0.butlast, false ' + bits3) + (bits0.last ∧ boolvar)' = bitsand(bits0, false ' + bits3 + boolvar '), # bits0 = 1

Rule argument

Additional information

Used simplifier rules: ⊦ # boolvar ' = 0 +1;% ⊦ #(bits + bits0) = # bits + # bits0;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ bits + boolvar ' ≠ [];