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Proof step 645 from proof bitsand-cast (previous step)

false ' + true ' + bits ≠ [] ∧ bits1 ≠ [], # bits1 = 2 + # bits, # bitsand(bits1, false ' + true ' + bits) < # bits1, bits3.first, # bits3 ≤ m, # bits1 ≤ # bits2 + # bitsand(bits1, false ' + true ' + bits) ⊦ bits3 + bits1 = [], bits2 + mklist(false, m) = [], bits1 = [], mklist(false, m) + bitsand(bits1, false ' + true ' + bits) = lastn(2 + # bits + m, bits2 + mklist(false, m) + bitsand(bits1, false ' + true ' + bits)), bits3 = [], m = 0, bits2 = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 646:
# bits1 = 2 + # bits, # bits1 ≤ # bits2 + # bitsand(bits1, false ' + true ' + bits), # bits3 ≤ m, bits3.first, # bitsand(bits1, false ' + true ' + bits) < # bits1 ⊦ bits1 = [], bits2 = [], m = 0, bits3 = [], mklist(false, m) + bitsand(bits1, false ' + true ' + bits) = lastn(2 + # bits + m, bits2 + mklist(false, m) + bitsand(bits1, false ' + true ' + bits)), bits2 + mklist(false, m) = [], bits3 + bits1 = []

Rule argument

Additional information

Used simplifier rules: ⊦ m + n = n + m;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ # bits = 0 ↔ bits = [];% ⊦ m < m + n ↔ n ≠ 0;% ⊦ m < n ∧ n = n0 → m < n0; (forward)% ⊦ m < n ∧ n ≤ n0 → m < n0; (forward)% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ boolvar ' + bits ≠ [];