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Proof step 703 from proof bitsand-cast (previous step)

2 + # bits + m ≤ #(mklist(false, # bits3) + bitsand(false ' + true ' + bits, bits1)), # bits1 = # bitsand(bits1, false ' + true ' + bits), 2 + # bits = # bits1, # bits3 < m ⊦ # bits3 = m, mklist(false, m) + bitsand(bits1, false ' + true ' + bits) = lastn(2 + # bits + m, mklist(false, # bits3) + bitsand(false ' + true ' + bits, bits1)), bits1 = [], bits2 + mklist(false, m) = [], bits3 + bits1 = [], bits3 = [], bits3.first

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 704:
# bits1 = # bitsand(bits1, false ' + true ' + bits), 2 + # bits = # bits1, # bits3 < m, 2 + # bits + m ≤ # bits3 + # bitsand(false ' + true ' + bits, bits1) ⊦ # bits3 = m, mklist(false, m) + bitsand(bits1, false ' + true ' + bits) = lastn(2 + # bits + m, mklist(false, # bits3) + bitsand(false ' + true ' + bits, bits1)), bits1 = [], bits2 + mklist(false, m) = [], bits3 + bits1 = [], bits3 = [], bits3.first

Rule argument

Additional information

Used simplifier rules: ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ # mklist(boolvar, n) = n;% ⊦ #(bits + bits0) = # bits + # bits0;% ⊦ m + n = n + m;% ⊦ (m + n0) + n1 = m + n0 + n1;