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Proof step 18 from proof bitsor-bi-zeroes (previous step)

⊦ bits3 = [], # bits3 = 1, bits2int(bitsor(bits3, false ') + bits1) = bits2uint(bits1), true ∈ bits3

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 19:
⊦ bits ≠ [] ∧ bits0 = false ' → bitsor(bits, bits0) = bits
Proof step 20:
bits3 ≠ [] ∧ false ' = false ' ⊦ bits3 = [], # bits3 = 1, bits2int(bits3 + bits1) = bits2uint(bits1), true ∈ bits3

Rule argument

name: or-rec-02 rotate: F subst: [bits0, bits] → [false ', bits3]

Additional information

Used terms: false ', bits3