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Proof step 20 from proof bitsor-bi-zeroes (previous step)

bits3 ≠ [] ∧ false ' = false ' ⊦ bits3 = [], # bits3 = 1, bits2int(bits3 + bits1) = bits2uint(bits1), true ∈ bits3

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information