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Proof step 21 from proof bitsor-bi-zeroes (previous step)

⊦ # bits3 = 1, bits2int(bits3 + bits1) = bits2uint(bits1), bits3 = [], true ∈ bits3

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 22:
⊦ ¬ bits.first ∧ bits ≠ [] → bits2int(bits) = bits2uint(bits)
Proof step 23:
¬(¬ (bits3 + bits1).first ∧ bits3 + bits1 ≠ []) ⊦ # bits3 = 1, bits2int(bits3 + bits1) = bits2uint(bits1), bits3 = [], true ∈ bits3
Proof step 25:
¬ (bits3 + bits1).first ∧ bits3 + bits1 ≠ [] ⊦ # bits3 = 1, bits2uint(bits3 + bits1) = bits2uint(bits1), bits3 = [], true ∈ bits3

Rule argument

seq: ⊦ ¬ bits.first ∧ bits ≠ [] → bits2int(bits) = bits2uint(bits) subst: [bits] → [bits3 + bits1] rotate: F spec: int2bits inst: name: bits2int-pos-02

Additional information

Used terms: bits3 + bits1