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Proof step 1 from proof bxor-zero (conclusion)

⊦ bxor(i, 0) = i

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ bxor(i, j) = bor(band(i, bcompl(j)), band(bcompl(i), j))
Proof step 3:
⊦ bor(band(i, bcompl(0)), band(bcompl(i), 0)) = i

Rule argument

name: bxor-def-logic rotate: F subst: [j, i] → [0, i]

Additional information

Used terms: 0, i