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Proof step 3 from proof bxor-zero (previous step)

⊦ bor(band(i, bcompl(0)), band(bcompl(i), 0)) = i

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: bcompl-num: ⊦ bcompl((* i)) = bits2int(bitsinvert(int2bits(i)));%band-minus-one: ⊦ band(~1, i) = i;%band-associativity: ⊦ band(i, band(i0, j)) = band(band(i, i0), j);%band-commutativity: ⊦ band(i, j) = band(j, i);%band-zero: ⊦ band(0, i) = 0;%bor-zero: ⊦ bor(i, 0) = i;% ⊦ bits2int(true ') = ~1;% ⊦ bitsinvert(false ') = true ';% ⊦ int2bits(0) = false ';