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Proof step 2 from proof cast-add-2pot (previous step)

0 < i ⊦ cast(i, j + 2 ^ i) = cast(i, j)

User applied rule cut formula

And obtained the following new goals

Proof step 3:
j + 2 ^ i = 1 * 2 ^ i + j, 0 < i ⊦ cast(i, j + 2 ^ i) = cast(i, j)

Rule argument

fma: j + 2 ^ i = 1 * 2 ^ i + j

Additional information

Used simplifier rules: ⊦ 1 * i = i;% ⊦ i * j * j0 = (i * j) * j0;% ⊦ i * j = j * i;% ⊦ i + j = i + i0 ↔ j = i0;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + j = j + i; Used formulas: j + 2 ^ i = 1 * 2 ^ i + j