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Proof step 3 from proof cast-add-2pot (previous step)

j + 2 ^ i = 1 * 2 ^ i + j, 0 < i ⊦ cast(i, j + 2 ^ i) = cast(i, j)

User applied rule insert equation

And obtained the following new goals

Proof step 4:
0 < i ⊦ cast(i, 1 * 2 ^ i + j) = cast(i, j)

Rule argument

pos: left 1 flags: discard

Additional information