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Proof step 1 from proof cast-law-mult (conclusion)

0 < i ⊦ cast(i, j * j0) = cast(i, cast(i, j) * cast(i, j0))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
0 < i ⊦ cast(i, j * j0) = cast(i, cast(i, j) * j0)
Proof step 3:
0 < i, 0 < i ⊦ cast(i, cast(i, j) * j0) = cast(i, cast(i, j) * cast(i, j0))

Rule argument

name: cast-law-mult-one rotate: F subst: [j0, j, i] → [j0, j, i]

Additional information

Used terms: j0, j, i