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Proof step 3 from proof cast-law-mult (previous step)

0 < i, 0 < i ⊦ cast(i, cast(i, j) * j0) = cast(i, cast(i, j) * cast(i, j0))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ i * j = j * i
Proof step 5:
0 < i, 0 < i ⊦ cast(i, j0 * cast(i, j)) = cast(i, cast(i, j) * cast(i, j0))

Rule argument

seq: ⊦ i * j = j * i subst: [j, i] → [j0, cast(i, j)] rotate: F spec: int-mult inst: name: commutativity

Additional information

Used terms: j0, cast(i, j)