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Proof step 3 from proof cast-law-sub-one-01 (previous step)

0 < i ⊦ cast(i, ~(j0 + ~ j)) = cast(i, j - cast(i, j0))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
0 < i ⊦ cast(i, ~ j) = cast(i, ~ cast(i, j))
Proof step 5:
0 < i, 0 < i ⊦ cast(i, ~ cast(i, j0 + ~ j)) = cast(i, j - cast(i, j0))

Rule argument

name: cast-law-neg rotate: F subst: [j, i] → [j0 + ~ j, i]

Additional information

Used terms: j0 + ~ j, i