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Proof step 5 from proof cast-law-sub-one-01 (previous step)

0 < i, 0 < i ⊦ cast(i, ~ cast(i, j0 + ~ j)) = cast(i, j - cast(i, j0))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
0 < i ⊦ cast(i, j + j0) = cast(i, cast(i, j) + j0)
Proof step 7:
0 < i, 0 < i, 0 < i ⊦ cast(i, ~ cast(i, cast(i, j0) + ~ j)) = cast(i, j - cast(i, j0))

Rule argument

name: cast-law-add-one rotate: F subst: [j0, j, i] → [~ j, j0, i]

Additional information

Used terms: ~ j, j0, i