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Proof step 7 from proof cast-law-sub-one-01 (previous step)

0 < i, 0 < i, 0 < i ⊦ cast(i, ~ cast(i, cast(i, j0) + ~ j)) = cast(i, j - cast(i, j0))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 8:
0 < i ⊦ cast(i, ~ j) = cast(i, ~ cast(i, j))

Rule argument

name: cast-law-neg rotate: T subst: [j, i] → [cast(i, j0) + ~ j, i]

Additional information

Used simplifier rules: ⊦ i + ~ j = i - j;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + j = j + i;% ⊦ ~(i - j) = j - i; Used terms: cast(i, j0) + ~ j, i