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Proof step 3 from proof cast-law-xor-one (previous step)

0 < i ⊦ cast(i, bor(band(j, bcompl(j0)), band(bcompl(j), j0))) = cast(i, bxor(cast(i, j), j0))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ bxor(i, j) = bor(band(i, bcompl(j)), band(bcompl(i), j))
Proof step 5:
0 < i ⊦ cast(i, bor(band(j, bcompl(j0)), band(bcompl(j), j0))) = cast(i, bor(band(cast(i, j), bcompl(j0)), band(bcompl(cast(i, j)), j0)))

Rule argument

name: bxor-def-logic rotate: F subst: [j, i] → [j0, cast(i, j)]

Additional information

Used terms: j0, cast(i, j)