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Proof step 5 from proof cast-law-xor-one (previous step)

0 < i ⊦ cast(i, bor(band(j, bcompl(j0)), band(bcompl(j), j0))) = cast(i, bor(band(cast(i, j), bcompl(j0)), band(bcompl(cast(i, j)), j0)))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
0 < i ⊦ cast(i, bor(j, j0)) = cast(i, bor(cast(i, j), j0))
Proof step 7:
0 < i, 0 < i ⊦ cast(i, bor(cast(i, band(j, bcompl(j0))), band(bcompl(j), j0))) = cast(i, bor(band(cast(i, j), bcompl(j0)), band(bcompl(cast(i, j)), j0)))

Rule argument

name: cast-law-or-one rotate: F subst: [j0, j, i] → [band(bcompl(j), j0), band(j, bcompl(j0)), i]

Additional information

Used terms: band(bcompl(j), j0), band(j, bcompl(j0)), i