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Proof step 10 from proof cast-max (previous step)

0 < i ∧ i ≠ 1, 0 < cast(i, j), i→n(i) -1 + 1 < # int2bits(cast(i, j)), 0 < i ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
0 < i, 0 < cast(i, j), 1 + (i→n(i) - 1) < # int2bits(cast(i, j)) ⊦ i = 1

Rule argument

Additional information

Used simplifier rules: ⊦ n -1 = n - 1;