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Proof step 5 from proof cast-max (previous step)

0 < cast(i, j), i→n(i - 1) + 1 < # int2bits(cast(i, j)), 0 < i ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ 0 < i ∧ i ≠ 1 → i→n(i - 1) = i→n(i) -1
Proof step 7:
¬(0 < i ∧ i ≠ 1), 0 < cast(i, j), i→n(i - 1) + 1 < # int2bits(cast(i, j)), 0 < i ⊦
Proof step 10:
0 < i ∧ i ≠ 1, 0 < cast(i, j), i→n(i) -1 + 1 < # int2bits(cast(i, j)), 0 < i ⊦

Rule argument

seq: ⊦ 0 < i ∧ i ≠ 1 → i→n(i - 1) = i→n(i) -1 subst: [i] → [i] rotate: F spec: intnat inst: name: abs-succ-02

Additional information

Used terms: i