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Proof step 16 from proof cast-mult-add (previous step)

0 < i ⊦ j0 % 2 ^ i < 0, cast(i, j * 2 ^ i + j0) = cast(i, j0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 17:
0 < i, 0 ≤ j0 % 2 ^ i ⊦ cast(i, j * 2 ^ i + j0) = cast(i, j0)

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)% ⊦ ¬ i < j ↔ j ≤ i;