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Proof step 2 from proof cast-mult-add (previous step)

0 < i ⊦ cast(i, j * 2 ^ i + j0) = cast(i, j0)

User applied rule cut formula

And obtained the following new goals

Proof step 3:
j0 % 2 ^ i < 0, 0 < i ⊦ cast(i, j * 2 ^ i + j0) = cast(i, j0)
Proof step 16:
0 < i ⊦ j0 % 2 ^ i < 0, cast(i, j * 2 ^ i + j0) = cast(i, j0)

Rule argument

fma: j0 % 2 ^ i < 0

Additional information

Used formulas: j0 % 2 ^ i < 0