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Proof step 4 from proof intshiftrsign-if (previous step)

⊦ bits2int(sublist(0, # int2bits(i), mklist(int2bits(i).first, i→n(band(j, 31))) + int2bits(i))) = (¬ i→n(band(j, 31)) < # int2bits(i) ⊃ (¬ 0 ≤ i ⊃ ~1;0);bits2int(sublist(0, # int2bits(i) - i→n(band(j, 31)), int2bits(i))))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
⊦ bits2int(sublist(0, # int2bits(i), mklist(¬ 0 ≤ i, i→n(band(j, 31))) + int2bits(i))) = (¬ i→n(band(j, 31)) < # int2bits(i) ⊃ (¬ 0 ≤ i ⊃ ~1;0);bits2int(sublist(0, # int2bits(i) - i→n(band(j, 31)), int2bits(i))))

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ i < j ↔ j ≤ i;% ⊦ int2bits(j).first ↔ j < 0;