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Proof step 5 from proof intshiftrsign-if (previous step)

⊦ bits2int(sublist(0, # int2bits(i), mklist(¬ 0 ≤ i, i→n(band(j, 31))) + int2bits(i))) = (¬ i→n(band(j, 31)) < # int2bits(i) ⊃ (¬ 0 ≤ i ⊃ ~1;0);bits2int(sublist(0, # int2bits(i) - i→n(band(j, 31)), int2bits(i))))

Heuristic if-then-else split applied rule case distinction

And obtained the following new goals

Rule argument

pos: right 1

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