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Proof step 6 from proof intshiftrsign-if (previous step)

¬ i→n(band(j, 31)) < # int2bits(i) ⊦ bits2int(sublist(0, # int2bits(i), mklist(¬ 0 ≤ i, i→n(band(j, 31))) + int2bits(i))) = (¬ 0 ≤ i ⊃ ~1;0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
# int2bits(i) ≤ i→n(band(j, 31)) ⊦ bits2int(sublist(0, # int2bits(i), mklist(¬ 0 ≤ i, i→n(band(j, 31))) + int2bits(i))) = (¬ 0 ≤ i ⊃ ~1;0)

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ m < n ↔ n ≤ m;