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Proof step 3 from proof shiftright-rec-8 (previous step)

j = i0 + 8, 8 ≤ j, 0 ≤ i, 0 < j, 0 ≤ j ⊦ i >> j = i / 256 >> i0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
0 ≤ i, 0 ≤ i0 ⊦ i >> (i0 + 8) = i / 256 >> i0

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)%i0 ≠ 0, i0 ≤ i ⊦ (* i) ≤ j → (* i0) ≤ j;%i0 ≠ 0, i0 < i ⊦ (* i) ≤ j → (* i0) < j;% ⊦ (* j) < i0 + (* j0) ↔ j - j0 < i0;% ⊦ i + j = j + i;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ (* j) ≤ i0 + (* j0) ↔ j - j0 ≤ i0;