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Proof step 4 from proof shiftright-rec-8 (previous step)

0 ≤ i, 0 ≤ i0 ⊦ i >> (i0 + 8) = i / 256 >> i0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
⊦ 0 ≤ i → i >> j = i / 2 ^ abs(j)
Proof step 6:
0 ≤ i, 0 ≤ i, 0 ≤ i0 ⊦ i / 2 ^ abs(i0 + 8) = i / 256 >> i0

Rule argument

name: shiftright-pos-div-01 rotate: F subst: [j, i] → [i0 + 8, i]

Additional information

Used terms: i0 + 8, i