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Proof step 6 from proof shiftright-rec-8 (previous step)

0 ≤ i, 0 ≤ i, 0 ≤ i0 ⊦ i / 2 ^ abs(i0 + 8) = i / 256 >> i0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
0 ≤ i, 0 ≤ i0 ⊦ i / 2 ^ (i0 + 8) = i / 256 >> i0

Rule argument

Additional information

Used simplifier rules: ⊦ i + j = j + i;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ 0 ≤ i → abs(i) = i;% ⊦ 0 ≤ i ∧ 0 ≤ j → abs(i + j) = abs(i) + abs(j);