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Proof step 7 from proof shiftright-rec-8 (previous step)

0 ≤ i, 0 ≤ i0 ⊦ i / 2 ^ (i0 + 8) = i / 256 >> i0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 8:
⊦ 0 ≤ i → i >> j = i / 2 ^ abs(j)
Proof step 9:
0 ≤ i / 256, 0 ≤ i, 0 ≤ i0 ⊦ i / 2 ^ (i0 + 8) = (i / 256) / 2 ^ abs(i0)

Rule argument

name: shiftright-pos-div-01 rotate: F subst: [j, i] → [i0, i / 256]

Additional information

Used simplifier rules: ⊦ 0 < j ∧ 0 ≤ i → 0 ≤ i / j; Used terms: i0, i / 256