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Proof step 9 from proof shiftright-rec-8 (previous step)

0 ≤ i / 256, 0 ≤ i, 0 ≤ i0 ⊦ i / 2 ^ (i0 + 8) = (i / 256) / 2 ^ abs(i0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
0 ≤ i, 0 ≤ i0 ⊦ i / 2 ^ (i0 + 8) = (i / 256) / 2 ^ i0

Rule argument

Additional information

Used simplifier rules: ⊦ 0 < j ∧ 0 ≤ i → 0 ≤ i / j;% ⊦ 0 ≤ i → abs(i) = i;