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Proof step 1 from proof shiftright-rec-pos (conclusion)

⊦ 0 ≤ i ∧ 0 < j → i >> j = i / 2 >> (j - 1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
0 ≤ i, 0 < j ⊦ i >> j = i / 2 >> (j - 1)

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)% ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward)