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Proof step 2 from proof shiftright-rec-pos (previous step)

0 ≤ i, 0 < j ⊦ i >> j = i / 2 >> (j - 1)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 3:
j = i0 + 1, 0 ≤ i, 0 < j ⊦ i >> j = i / 2 >> i0

Rule argument

seq: ⊦ i0 = i - j ↔ i = i0 + j subst: [i, j, i0] → [j, 1, i0] rotate: T spec: int-abs inst: name: elim-sub

Additional information

Used simplifier rules: ⊦ i0 = i - j ↔ i = i0 + j; (elim) Used terms: j, 1, i0