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Proof step 3 from proof shiftright-rec-pos (previous step)

j = i0 + 1, 0 ≤ i, 0 < j ⊦ i >> j = i / 2 >> i0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
0 ≤ i, 0 ≤ i0 ⊦ i >> (i0 + 1) = i / 2 >> i0

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)% ⊦ i + j = j + i;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ ~1 < i ↔ 0 ≤ i;% ⊦ (* j) < i0 + (* j0) ↔ j - j0 < i0;