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Proof step 4 from proof shiftright-zero (previous step)

⊦ bits2int(sublist(0, 1, mklist(false, i→n(j)) + false ')) = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
⊦ ¬ true ∈ bits ∧ bits ≠ [] → bits2int(bits) = 0
Proof step 6:
¬(¬ true ∈ sublist(0, 1, mklist(false, i→n(j)) + false ') ∧ sublist(0, 1, mklist(false, i→n(j)) + false ') ≠ []) ⊦ bits2int(sublist(0, 1, mklist(false, i→n(j)) + false ')) = 0

Rule argument

seq: ⊦ ¬ true ∈ bits ∧ bits ≠ [] → bits2int(bits) = 0 subst: [bits] → [sublist(0, 1, mklist(false, i→n(j)) + false ')] rotate: F spec: int2bits inst: name: bits2int-zero-01

Additional information

Used terms: sublist(0, 1, mklist(false, i→n(j)) + false ')