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Proof step 6 from proof shiftright-zero (previous step)

¬(¬ true ∈ sublist(0, 1, mklist(false, i→n(j)) + false ') ∧ sublist(0, 1, mklist(false, i→n(j)) + false ') ≠ []) ⊦ bits2int(sublist(0, 1, mklist(false, i→n(j)) + false ')) = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
true ∈ sublist(0, 1, mklist(false, i→n(j)) + false ') ⊦ bits2int(sublist(0, 1, mklist(false, i→n(j)) + false ')) = 0

Rule argument

Additional information

Used simplifier rules: ⊦ sublist(0, n, bits) = [] ↔ n = 0;