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Proof step 7 from proof shiftright-zero (previous step)

true ∈ sublist(0, 1, mklist(false, i→n(j)) + false ') ⊦ bits2int(sublist(0, 1, mklist(false, i→n(j)) + false ')) = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 8:
⊦ sublist(m, n, bits) = firstn(n, restn(m, bits))
Proof step 9:
true ∈ firstn(1, restn(0, mklist(false, i→n(j)) + false ')) ⊦ bits2int(firstn(1, restn(0, mklist(false, i→n(j)) + false '))) = 0

Rule argument

seq: ⊦ sublist(m, n, bits) = firstn(n, restn(m, bits)) subst: [bits, n, m] → [mklist(false, i→n(j)) + false ', 1, 0] rotate: F spec: list-del inst: bitlista name: sublist-def

Additional information

Used terms: mklist(false, i→n(j)) + false ', 1, 0