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Proof step 9 from proof shiftright-zero (previous step)

true ∈ firstn(1, restn(0, mklist(false, i→n(j)) + false ')) ⊦ bits2int(firstn(1, restn(0, mklist(false, i→n(j)) + false '))) = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
true ∈ firstn(1, mklist(false, i→n(j)) + false ') ⊦ bits2int(firstn(1, mklist(false, i→n(j)) + false ')) = 0

Rule argument

Additional information

Used simplifier rules: ⊦ restn(0, bits) = bits;