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Proof step 18 from proof shiftzero-minus-one (previous step)

0 < n ⊦ j = 0, n = 0, bits2int(firstn(# mklist(true, n), mklist(false, i→n(j)) + mklist(true, n))) = bits2int(firstn(1 + n, mklist(false, i→n(j)) + false ' + mklist(true, n)))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 19:
⊦ j = 0, bits2int(firstn(n, mklist(false, i→n(j)) + mklist(true, n))) = bits2int(firstn(1 + n, mklist(false, i→n(j)) + false ' + mklist(true, n))), n = 0

Rule argument

Additional information

Used simplifier rules: ⊦ 0 < n ↔ n ≠ 0;% ⊦ # mklist(boolvar, n) = n;% ⊦ m < n → n ≠ 0;