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Proof step 19 from proof shiftzero-minus-one (previous step)

⊦ j = 0, bits2int(firstn(n, mklist(false, i→n(j)) + mklist(true, n))) = bits2int(firstn(1 + n, mklist(false, i→n(j)) + false ' + mklist(true, n))), n = 0

User applied rule cut formula

And obtained the following new goals

Proof step 20:
mklist(false, i→n(j)) + false ' + mklist(true, n) = false ' + mklist(false, i→n(j)) + mklist(true, n) ⊦ j = 0, bits2int(firstn(n, mklist(false, i→n(j)) + mklist(true, n))) = bits2int(firstn(1 + n, mklist(false, i→n(j)) + false ' + mklist(true, n))), n = 0
Proof step 30:
⊦ mklist(false, i→n(j)) + false ' + mklist(true, n) = false ' + mklist(false, i→n(j)) + mklist(true, n), j = 0, bits2int(firstn(n, mklist(false, i→n(j)) + mklist(true, n))) = bits2int(firstn(1 + n, mklist(false, i→n(j)) + false ' + mklist(true, n))), n = 0

Rule argument

fma: mklist(false, i→n(j)) + false ' + mklist(true, n) = false ' + mklist(false, i→n(j)) + mklist(true, n)

Additional information

Used formulas: mklist(false, i→n(j)) + false ' + mklist(true, n) = false ' + mklist(false, i→n(j)) + mklist(true, n)