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Proof step 2 from proof denom-neg-02 (
previous step
)
ri ≠ 0r ⊦ ∃ i, j. ri = rational(i, j) ∧ ri.num = i ∧ ri.denom = j ∧ 0 < j ∧ gcd(i, j) = 1
Lemma
exrat-gcd1