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Theorem exrat-gcd1

ri ≠ 0r ⊦ ∃ i, j. ri = rational(i, j) ∧ ri.num = i ∧ ri.denom = j ∧ 0 < j ∧ gcd(i, j) = 1

Type: A user defined theorem
Validity: The proof is valid.
Features:
Comment:
Used by: denom-neg-02, num-neg-03, root-is-irrational,
Used by units in proved state:
Proof exists?: Yes

View the proof

Infos about the proof

Proved?: Yes
Interactions: 1
Proof steps: 2
Used lemmas: num-zero-denum-one, gcd-num-one, denom-pos-01, make, zero-def,
Used spec theorems:
- Used simplifier rules:
  - int-abs/lels
  - int-gcd/gcd-one-01