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Proof step 5 from proof div-def-01 (previous step)

0 < j, 0 < j0, i ≠ 0 → rational(abs(i), j) / rational(abs(i0), j0) = rational(abs(i) * j0, j * abs(i0)) ⊦ rational(i, j) / rational(i0, j0) = rational(i * j0, j * i0), i0 = 0

User applied rule cut formula

And obtained the following new goals

Proof step 6:
i = 0, 0 < j, 0 < j0, i ≠ 0 → rational(abs(i), j) / rational(abs(i0), j0) = rational(abs(i) * j0, j * abs(i0)) ⊦ rational(i, j) / rational(i0, j0) = rational(i * j0, j * i0), i0 = 0
Proof step 12:
0 < j, 0 < j0, i ≠ 0 → rational(abs(i), j) / rational(abs(i0), j0) = rational(abs(i) * j0, j * abs(i0)) ⊦ i = 0, rational(i, j) / rational(i0, j0) = rational(i * j0, j * i0), i0 = 0

Rule argument

fma: i = 0

Additional information

Used formulas: i = 0