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Proof step 6 from proof div-def-01 (previous step)

i = 0, 0 < j, 0 < j0, i ≠ 0 → rational(abs(i), j) / rational(abs(i0), j0) = rational(abs(i) * j0, j * abs(i0)) ⊦ rational(i, j) / rational(i0, j0) = rational(i * j0, j * i0), i0 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: zero-num-01: ⊦ rational(0, i * j) = rational(0, 1);% ⊦ i * j = j * i;% ⊦ i * j * j0 = (i * j) * j0;% ⊦ i * 0 = 0;