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Proof step 7 from proof div-def-01 (previous step)

0 < j, 0 < j0 ⊦ i0 = 0, rational(0, j) / rational(i0, j0) = rational(0, 1)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 8:
⊦ rational(0, j) = rational(0, 1)
Proof step 9:
0 < j, 0 < j0 ⊦ i0 = 0, rational(0, 1) / rational(i0, j0) = rational(0, 1)

Rule argument

name: zero-num rotate: F subst: [j] → [j]

Additional information

Used terms: j